Name: Third Test, Page 5 of 6 rectangular loop of wire of dimensions 20.0cm by 3

Question

Name: Third Test, Page 5 of 6 rectangular loop of wire of dimensions 20.0cm by 30.0cm, with internal resistance of is brought, at constant speed of 3.00 m/s, into a region with uniform magnetic 4. A 3.75 field.= 2.50T, into the page. The loop is placed flat on the page. (1) (5 points) Find an expression for the magnetic flux through the loop when a total distance r has been pushed in. Your answer must depend on the variable r. Is the magnetic flux increasing or decreasing as the loop goes in? 30 cm 20 cm (Il) (10 points) Find an expression for the induced emf through the loop, remember that z/t-t, and thate= Mch. (II) (5 points) Find the induced current in the loop using Ohm's Law. (IV) (5 points) What is the direction of the induced magnetic field in the loop and whe is the direction of the induced current in the loop?

Explanation / Answer

I) for the magnetic flux

when x distance has been pushed

magnetic flux = B * 0.20 * x

magnetic flux = 2.50 * 0.20 * x

magnetic flux = 0.50 * x T.m^2

II)

for the induced emf

induced emf = d/dt(magnetic flux)

induced emf = 0.50 * dx/dt

induced emf = 0.50*v

iii)Uisng Ohm's law

induced current = induced emf/R

induced current = 0.50 * 3/3.75

induced current = 0.40 A

iv)

as the flux in loop is increasing

the induced field will be in oposite direction , hence , the induced field will be out of the page

which by right hand rule implied induced current is Counterclockwise

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