A boy throws a ball into the air as hard as he can and then run as fast as he ca

Question

A boy throws a ball into the air as hard as he can and then run as fast as he can under the ball in order to catch it. If his maximum speed in throwing the ball is 20 m/s and his best time for a 20-m dash is 3 seconds, how high does the ball rise? A boy throws a ball into the air as hard as he can and then run as fast as he can under the ball in order to catch it. If his maximum speed in throwing the ball is 20 m/s and his best time for a 20-m dash is 3 seconds, how high does the ball rise? A boy throws a ball into the air as hard as he can and then run as fast as he can under the ball in order to catch it. If his maximum speed in throwing the ball is 20 m/s and his best time for a 20-m dash is 3 seconds, how high does the ball rise?

Explanation / Answer

Speed = 20/3 = 6.67 m/s

velocity of throw = 20 m/s

The vertical velocity then must complete a right triangle with hypotenuse 20 and one leg 6.67.

20^2 = 6.67^2 + v^2

v = 18.85 m/s

Vertical velocity = 0 at the top

so change in vertical velocity = 18.85

t = v/ a = 18.85/9.8 = 1.92 s

S = ut + 0.5gt^2

= 0 + 0.5*9.8*1.92^2

= 18.14 m

so the ball rised 18.14 m

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