(13%) Problem 4: In the circuit diagram R,-SR and R,-15R, where R = 23 . The pow

Question

(13%) Problem 4: In the circuit diagram R,-SR and R,-15R, where R = 23 . The power dissipated in resistor 2 is P 2.9 W. ©theexpertta.com 50% Part (a) What is the voltage across the battery in volts? Grade Summa Deductions Potential 49.8985 5% 95% cosO tan() | 789 HOME Sin Submissions cotanasin0 acos0 atan acotan sinhO Co tempts remaining: 14 (5% per attempt) detailed view cotanhO 5% END Degrees Radians NO BACKSPACE DEL CLEAR Submit Hint I give up! Hints: 2% deduction per hint. Hints remaining: 3 Feedback: 2% deduction per feedback. 50% Part (b) How much power, Ps, is the source supplying, in watts?

Explanation / Answer

P = I^2 R

2.9 = I^2 (15 x 23)

I = 0.0917 A

(A) V = I (R1 + R2)

= 0.0917 x 23 (5 + 15)

= 42.2 Volt

(B) P = VI = 3.9 W

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