« previous | 8 of 10 | next Problem 20.48 What is the magnitude of the electric

Question

« previous | 8 of 10 | next Problem 20.48 What is the magnitude of the electric field? E= 559 V/ml A given system has the equipotential surfaces shown in the figure (Fiqure 1) Submit My Answers Give Up Correct Part B What is the direction of the electric field? - 243 ° from the +x axis Submit My Answers Give Up Correct Figure 1 of 1 Part C cm What is the shortest distance one can move to undergo a change in potential of 10.0 V? V=30.0 V d- 15.2 x (cm) 8 10 1 V=20.0 V Submit My Answers Give Up V= 10.0 V V=0.00 V Incorrect; Try Again; 5 attempts remaining Continue

Explanation / Answer

The shortest distance(d) one can move to undergo a change in potential(V) is given by,

d = V/E ; where E is the electric field in the region.

Now V = 10 V ,E = 559 V/m

Thus d = 10/559 = 0.018m = 1.8 cm

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