Blocks in an Elevator Ranking Task Part A Assume the elevator is at rest. Rank t

Question

Blocks in an Elevator Ranking Task Part A Assume the elevator is at rest. Rank the magnitude of the forces. Three blocks are stacked on top of each other inside an elevator as shown in (Figure 1) Rank from largest to smallest. To rank items as equivalent, overlap them. Answer the tollawing questions with reterence to the eight torces defined folkows. Hints the torce ot the 3 kg block on the kg block Reset Help the forco of the 2 kg block on the 3 kg block, 2 on 3 the force of the 3 kg block on the 1 kg block, the force of the 1 kg block on the 3 kg block, .the torce ot the 2 kg block on the 1 kg block the force of the 1 kg block on the 2 kg block, the force of the 1 kg block on the floor, Fi on foor argest smallest and the force of the floor on the 1 kg block, Faoor ou 1 loor un 1 rigure 1 ef 1 The rrrrect rankinn rannat he dr termined Submit MyAnswers Give Up Incorrect; Try Again; 5 attempts remaining The 3 kg block and the 1 kg block do not touch, and therefore they exert zero force on each other. No magnitude can be less than zero. Part B 2 kg This question will be shown after you complete previous question(s). Continue

Explanation / Answer

Force acting on the blocks:

Force acting on the 2 kg block by the 3 kg block,

F32 = m3*g = 3*9.8 = 29.4 N

Force acting on the 3 kg block by the 2 kg block,

F23 = 3*9.8 = 29.4 N

Force acting on the 3 kg block by the 1 kg block,

F31 = 0 (This is because there is no contact between block 1 and block 3.)

Force acting on the 1 kg block by the 3 kg block,

F13 = 0 ( because there is no contact between block 1 and block 3)

Force acting on the 1 kg block by the 2 kg block,

F12 = (m2 +m3)*g = (2+3)*9.8 = 49N

Force acting on the 2 kg block by the 1 kg block,

F21 = 5*9.8 = 49 N

Force acting on the floor by the 1 kg block,

F1, floor = (m1 +m2+m3)*g = (1+2+3)*9.8 = 58.8 N

Force acting on the 1 kg block by the floor,

Ffloor,1 = (m1 +m2+m3)*g = (1+2+3)*9.8 = 58.8 N

From the values for forces obtained from the calculation, it can be represented as,

Ffloor,1 = F1,floor > F21 = F12 > F23 = F32 > F31 = F13

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