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Two Systems of Charges Points: 2 Figure 1 Figure 2 +q -q -q -q +q +q Consider tw

ID: 1776555 • Letter: T

Question

Two Systems of Charges Points: 2 Figure 1 Figure 2 +q -q -q -q +q +q Consider two separate systems, each with four charges of magnitude q arranged in a square of length L as shown above, Points a and c are in the center of their squarés while points b and d are half way between the lower two charges. Select True or False for the following statements The electric potential at b is zero The electric potential at c is zero. The electric field at c is zero. The electric potential at d is zero. B The electric field at b is zero. B The electric field at a is zero. The electric potential at a is zero. The electric field at d is zero. Submit Anewer Tries 0/40 Bsing the diaga m above find the magnitude of the electric field at point d. DATA: q= 0.850 pC, L= 0.40 m. Submit Answer Tries 0/40

Explanation / Answer

distance of each charge from the center point (a and c)=L1=L/sqrt(2)

distance of upper two charges from b and d=L2=sqrt(L^2+(L/2)^2)=sqrt(5)*L/2

distance of lower two charges from b and d=L3=L/2

potential due to a charge Q at a distance D=k*Q/D

where k=coloumb’s constant

electric field at a distance of D due to a charge Q=k*Q/D^2

direction of field from +ve charge is away from the charge and direction of field due to -ve charge is towards the charge.

part 1:

potential at b=(k*q/L3)+(-k*q/L3)+(k*q/L2)+(-k*q/L2)

=0

so the statement is true.

part 2:

electric potential at c=(k*q/L1)+(k*q/L1)+(-k*q/L1)+(-k*q/L1)

=0

part 3:

electric field at c:

as the charges are not symmetrical, field due to the charges wont cancel out each each other.

so the field is not zero.

hence the statement is false.

part 4:

electric potential at d=(k*q/L3)+(k*q/L3)+(-k*q/L2)+(-k*q/L2)

which is not zero.

hence the statement is false.

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