3 59 The gravitational constant G = 6.67 x 10-11 Nm,kg 8. a. (5 points) What is

Question

3 59 The gravitational constant G = 6.67 x 10-11 Nm,kg 8. a. (5 points) What is the to gravity a mass of 2.0 x 1030 kg and a radius of 7.0 x 10 m? lration due to gravity on the surface of the sun, a star with (Don't stand there!) b. (5 points) In billions of years, the sun will become a red giant. It will have the same mass (2.0 x 10 kg) but it's radius will swell to 1.5 x 101 m. What will be the acceleration due to gravity on the surface of the sun in the future? . A satellite moves in a circular orbit 1100 km above the earth's surface. The mass of the arth is 5.98 x 1024 kg. (1 point) The radius of the earth is 6370 km. What is the satellite's distance in meters om the center of the Earth? (5 points) What is the speed of the satellite (in m/s)? 5 points) What is the satellite's orbital period (in hours)?

Explanation / Answer

Q8.

part a:

acceleration due to gravity on sun=G*M/R^2

=6.67*10^(-11)*2*10^30/(7*10^8)^2

=272.24 m/s^2

part b:

acceleration due to gravity

=6.67*10^(-11)*2*10^30/(1.5*10^11)^2

=0.00593 m/s^2

Q9.

mass of the earth=5.98*10^24 kg

let speed of the satellite be v m/s.

then balancing gravitational force with centripetal force,

G*M*m/R^2=m*v^2/R

==>6.67*10^(-11)*5.98*10^24/(1100*1000+6370*1000)=v^2

==>v=7307.2 m/s

speed of the satellite is 7307.2 m/s.

part b:

satellite’s orbital period=circumference/speed

=2*pi*(1100*1000+6370*1000)/7307.2

=6423.2 seconds

=1.7842 hours

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