In the circuit shown below the 4 bulbs are identical and have a resistance of 85
ID: 1777159 • Letter: I
Question
In the circuit shown below the 4 bulbs are identical and have a resistance of 85 each. The battery supplies a voltage of 40 V. S1, S2, and S3 represent switches.
http://www.webassign.net/ncsuplseem2/4-post-06.gif
(a) S1 and S2 are closed while S3 is open. What is the current through each bulb?
bulb 1
bulb 2
bulb 3
bulb 4
(b) S3 is closed while S1 and S2 are open. What is the current through each bulb?
bulb 1
bulb 2
bulb 3
bulb 4
(c) S2 and S3 are closed while S1 is open. What is the current through each bulb?
bulb 1
bulb 2
bulb 3
bulb 4
(d) S1 and S3 are closed while S2 is open. What is the current through each bulb?
bulb 1
bulb 2
bulb 3
bulb 4
(e) All three switches are closed. What is the current through each bulb?
bulb 1
bulb 2
bulb 3
bulb 4
Explanation / Answer
(a)
there is a short circuit from Bulb 1 to Bulb 2,
Requ = R1 +R2 = 85+85 = 170 ohms,
current through each of Bulbs 1 and 2 is
V =IR
I = 40/170 = 0.235 amps.
No current through 3 and 4.
(b)
Bulbs 1,3,4 are in series,
Requ = 85+85+85 = 255 ohms
current through 1,3,4 is
I = 40/255 = 0.1568 amps.
No current through Bulb 2.
(c)
Bulbs 1 and 3 are in series with the parallel-resistance combination of Bulbs 2 and 4.
Requ = 2.5 * 85 = 212.5
current through Bulbs 1 and 3 is
I = 40/212.5 = 0.188 amps
current through Bulbs 2 and 4, 0.094 amps each.
(d)
Bulb 1 is in series with a parallel combination whose two branches are
(i) Bulb 2 and (ii) Bulbs 3 and 4 in series.
R-equiv for the whole circuit is
85 + 1/(1/85+1/170) = 141.67 ohms.
Current through Bulb 1 is
I = 40 / 141.67 = 0.282 amps.
current in Bulb 2 is I = 0.188 amps,
current through Bulbs 3 and 4 is I = 0.094 amps.
(e)
no current will go through Bulb 3,
Requ = 1.5 x 85 ohms = 127.5 ohms.
Current through Bulb 1 is I = 0.3137 amp,
currents through Bulbs 2 and 4 are I = 0.157 amp each
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