1) You are trying to find q/m , the charge-to-mass ratio for a charged particle.

Question

1) You are trying to find q/m, the charge-to-mass ratio for a charged particle. There is a region of magnetic field magnitude 27.3 T pointing out at you.

- First: the particle passes between charged parallel plates that create an electric field of magnitude 21.8 N/C and perpendicular to B. The particle passes through undeflected.

- Second: the particle emerges from the plates, and B causes the particle to moves in a circle of radius 15.5 cm.

Find the charge-to-mass ratio q/m for this particle, in C/kg.

2) A cylindrical metal wire (length 65.9 m, end diameter 0.873 cm, mass density 3.14 kg/m3) carries current 48.9 A perpendicular the Earth's magnetic field of 6.43 T. Find the ratio FM/Fg, the magnitude of the force due to magnetism divided by the force due to gravity.

Explanation / Answer

during first phase :

E = electric field = 21.8 N/C

B = magnetic field = 27.3 T

v = speed of charge

E = v B

21.8 = 27.3 v

v = 0.8 m/s

Phase 2 :

r = radius = 0.155 m

m = mass

using the formula

r = mv/(qB)

q/m = v/(Br) = (0.8)/(27.3 x 0.155) = 0.19

Related Questions

Navigate

• Browse (All)
• Browse 1
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.