You pull with a force of 215 N on a rope that is attached to a block of mass 30

Question

You pull with a force of 215 N on a rope that is attached to a block of mass 30 kg, and the block slides across the floor at a constant speed of 1.5 m/s. The rope makes an angle of 25 degrees with the horizontal dp What is the direction of dt of the block? What is the net force on the block? 02 N Which objects exert forces on the block with nonzero x-components? floor you rope Earth What is the x-component of the tension force exerted by the rope on the block? (A component may be positive or negative) What is the x-component of the force exerted by the floor on the block (the friction force)? Which objects exert forces on the block with nonzero y components? Earth you rope floor What is the y-component of the force exerted by the rope on the block? What is the y-component of the force exerted by the Earth on the block? Earth What is the y-component of the force exerted by the floor on the block (sometimes called the "normal" force, because it is perpendicular to the floor)?

Explanation / Answer

Direction of dp/dt is the same as the direction of the velocity.

This means direction of dp/dt is towards +x-axis.

Net forces on the block -

Fx = 215 * cos25 = 195 N

Fy = 215 * sin25 - 30*9.8 = 90.9 - 294 = -203.1 N

Which object exert forces on the block with non-zero x-component -

Option (3) rope is the correct answer.

As we have calculated earlier -

Fx = 195 N

Since the block is moving with constant velocity

So, x-component of frictional force = 0

Option (4) floor is the correct answer.

FTy = 90.9 N

F(Earth)y = -203.1 N

F(N)s = -203.1 N

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