6A 0225kg mass is being ngne 57 When the mass is at the bo oftt 7 The figure bel
ID: 1777886 • Letter: 6
Question
Explanation / Answer
6)given,
m = 0.275 kg ; L = 0.575 m ; v = 1.25 m/s ;
We need to find the tension in the string when it is at the bottom of the circle.
We know that at the bottom of vertical circle:
T(bottom) = mv^2/R + mg
T(bottom) = 0.275 (1.25^2/0.575 + 9.81) = 3.45 N
Hence, T = 3.45 N
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