B. If the particles are still initially held 5.00 nm apart but both particles ar
ID: 1778009 • Letter: B
Question
B. If the particles are still initially held 5.00 nm apart but both particles are released, when they are 2.55 nm away from each other, how would Particle I's speed compare to the speed used in part (a) above? (Assume that Particle II's mass is not the same as Particle I's; you should be able to answer this without performing a detailed calculation.)
Particle I would be faster than it was in (a)
Particle I would be moving at the same speed that it had in (a)
Particle I would be slower than it was in (a)
To answer this at all, Particle II's mass would be needed
Particle I's speed is unknown but it will definitely be the same as Particle II's
Explanation / Answer
a) d = 5 x 10-9 m, v = 119000 m/s , r = 2.55 x 10-9 m , m = 1.21 x 10-22 kg
conserving energy,
-kq2/d = -kq2/r + 0.5mv2
=> q = sqrt[0.5mv2dr/k(d-r)]
=> q = sqrt[0.5 x 1.21 x 10-22 x 1190002 x 5 x 10-9 x 2.55 x 10-9/(9 x 109 x 2.45 x 10-9)]
=> q = 7.0384243 x 10-16 C
b) as particles potential energy will be same as in case a). => total final kinetic energy will be same as the kinetic energy of particle 1 in case a). Though it will be divided in both the particles. => Particle I would be slower than it was in (a)
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.