Let I1 be 2 mA in the figure below. What is the voltage drop across the 2 kOhm r

ID: 1778140 • Letter: L

Question

Let I1 be 2 mA in the figure below. What is the voltage drop across the 2 kOhm resistor in the upper right? You should NOT have to do a lot of calculations.

(a.)6 V with the higher voltage at the top end of the resistor.

(b.)4 V with the higher voltage at the top end of the resistor.

(c.)14 V with the higher voltage at the top end of the resistor.

(d.)6 V with the higher voltage at the bottom end of the resistor.

(e.)14 V with the higher voltage at the bottom end of the resistor.

24 V 6 V 1 > 11

Explanation / Answer

Here , for I1 = 2 mA

current in 4 kOhm = 5 mA

Using Current law at right node

5 + 2 - I2 = 0

I2 = 7 mA

Now, for 2 kOhm

voltage across 2 kOhm = 2 * 7 V

voltage across 2 kOhm = 14 V

lower point will be at the higher potential

(e.)14 V with the higher voltage at the bottom end of the resistor.

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Let I1 be 2 mA in the figure below. What is the voltage drop across the 2 kOhm r

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