FULL SCREEN PRINTER VERSION BACK NEXT ullet is moving horizontally with a veloci

Question

FULL SCREEN PRINTER VERSION BACK NEXT ullet is moving horizontally with a velocity of +356 m/s, where the sign + indicates that it is moving to the A 5.65-g b right (see part a of the drawing). The bullet is approaching two blocks resting on a horizontal frictionless surface. Air resistance is negligible. The bullet passes completely through the first the second one, as indicated in part b. Note that both blocks are moving after the collision with the bulle the first block is 1248 g, and its velocity is +0.627 m/s after the bullet passes through it. The mass of the second block is 1642 g. (a) What is the velocity of the second block after the bullet imbeds itself? (b) Find the ratio of the total kinetic energy after the collision to that before the collision. block (an inelastic collision) and embeds itself in 356ms Block 2 (a) Before collision +0.627m/s block 2 mslock 1 - 1248 m block 2 642g mbuilet 5.658 (a) vblock2 = Number Units Units (b) KEarter/KEbefore = Number l Iranscript Delgado Data-SLCC Summe...

Explanation / Answer

Use conservation of momentum here

where p = m*v

so pi = m*v1 = 0.00565kg*356m/s = 2.01 kg-m/s

pf = m1*0.627 + (m2+mb)*v = 1.248*0.627 + (1.642 + 0.00565)*v = 0.782 + 1.64765v

so v = (2.01 - 0.782)/1.64765 = 0.745 m/s

b) Kafter = 1/2*1.248*0.627^2 + 1/2*( 1.64765)*0.745^2 = 0.703J

K before = 1/2*0.00565*356^2 = 358 J

So the ratio = 0.703/358 = 1.96 x 10^-3

Related Questions

Navigate

• Browse (All)
• Browse F
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.