iPad 7:34 AM 72% usu34ny. Assign 6 Begin Date: 1011/2017 9:00:00 AM -Due Date: 1
ID: 1779220 • Letter: I
Question
iPad 7:34 AM 72% usu34ny. Assign 6 Begin Date: 1011/2017 9:00:00 AM -Due Date: 10/16/2017 9:00.00 AM End Date: 10/18/2017 9:00:00 AM (17%) Problem 6: A young kid of mass m = 26 kg is swinging on a swing. The length from the top of the swing set to the seat is L- 4.3 m.The girl is attempting to swing all the way around in a full circle. ignment Status lick here for letailed view Otheexpertta.com blem Status 1 Completed 2 Completed 33% Part (a) What is the minimum speed in meters per second, the girl must be moving with at the top of the path in order to make a full circle? Partial Partial Grade Summary Doductions Potential 0% 1 00% cos) atan acotan) sinh0 ODegrees Radians tan() acoso sino Attempes remaining: 5% per attempt detailed lew cotanoasinO Hints:-% dedaction per hint Hints remaining: 2 Feedback:0% deduction per feedhack 33% Part (b) Assuming the girl is traveling at the speed found in part (a), what is their apparent weight, w in newtons at the top of their path? (At the top, the girl is upside-down.) 33% Part (c) If the velocity at the bottom is the same as the velocity at the top from part (a) what is the girl's apparent weight, in newtons, at the very bottom of the path?Explanation / Answer
The centripetal acceleration at the top of the circle would have to be a minimum 1g (9.8m/sec^2).
This in turn means the acceleration at the bottom would be (g+g) = 2g, or 19.6m/sec^2.
The force encountered at the bottom will be (m x 2g) = 26 x 19.6 = 509.6N.
a) Minimum V = sqrt.(f*r/m) = sqrt.(509.6 x 4.3)/26, = 9.18m/sec.
b) Apparent weight at top = 0N.
c) Apparent weight at the bottom = (m x 2g) = 26 x 19.6 = 509.6N
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