A 5.46g bullet leaves the muzzle of a rifle with a speed of 301 m/s. What force

Question

A 5.46g bullet leaves the muzzle of a rifle with a speed of 301 m/s. What force (assumed constant) is exerted on the bullet while it is traveling down the 0.796 m long barrel of the rifle? (in N)
A: 2.66×102 B: 3.11×102 C: 3.64×102 D: 4.25×102 E: 4.98×102 F: 5.82×102 G: 6.81×102 H: 7.97×102 A 5.46g bullet leaves the muzzle of a rifle with a speed of 301 m/s. What force (assumed constant) is exerted on the bullet while it is traveling down the 0.796 m long barrel of the rifle? (in N)
A: 2.66×102 B: 3.11×102 C: 3.64×102 D: 4.25×102 E: 4.98×102 F: 5.82×102 G: 6.81×102 H: 7.97×102 A 5.46g bullet leaves the muzzle of a rifle with a speed of 301 m/s. What force (assumed constant) is exerted on the bullet while it is traveling down the 0.796 m long barrel of the rifle? (in N)
A: 2.66×102 B: 3.11×102 C: 3.64×102 D: 4.25×102 E: 4.98×102 F: 5.82×102 G: 6.81×102 H: 7.97×102

Explanation / Answer

Use v2 = u2 + 2aS

3012 = 0 + 2a(0.796)

=> a = 56910.176 m/s2

so, force on the bullet will be:

F = ma = 5.46 x 10-3 x 56910.176 = 310.73 N [option B].

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