previous Problem 4.52 Part A Ships A and B leave port together. For the next two

Question

previous Problem 4.52 Part A Ships A and B leave port together. For the next two hours, ship A travels at 35.0 mph in a direction 55.0° west of north while the ship B travels 20.0 east of north at 40.0 mph What is the distance between the two ships two hours after they depart? Express your answer with the appropriate units. | Value Units Submit My Answers Give Up Part B What is the speed of ship A as seen by ship B? Express your answer with the appropriate units. Value Units Submit My Answers Give Up

Explanation / Answer

Part A:

Ship A makes an angle of 45° with West. And after 2 hours its distance is 70 mile.

Hence its components are (-70*cos(45°), 70*sin(45°))

Similarly for ship B, the components after 2 hours are (80*cos(70°), 80*sin(70°))

Hence, the distance between them is given by:

s² = {80*cos(70°) + 70*cos(45°)}² + {80*sin(70°) - 70*sin(45°)}²

= 5907 + 659 = 6566

=> s = 81.03 mile

he distance between the ships after two hours = 81.03 miles.

Part B:

Speed of the ship A as seen by ship B is given by:

81.03/2 = 40.51 mph.

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