Suppose you want to determine the electric field in a certain region of space. Y

Question

Suppose you want to determine the electric field in a certain region of space. You have a small object of known charge and an instrument that measures the magnitude and direction of the force exerted on the object by the electric field. (a) The object has a charge of +25.0 C and the instrument indicates that the electric force exerted on it is 25.0 N, due east. What are the magnitude and direction of the electric field? E = (b) What are the magnitude and direction of the electric field if the object has a charge of -30.0 C and the instrument indicates that the force is 30.0 N, due west? E =

Explanation / Answer

Given,

(a)Q = 25 uC ; F = 25 uN

we know that the force due to electric field is given by:

F = q E => E = F/q

E = 25 x 10^-6 N/25 x 10^-6 C = 1 N/C

Hence, E = 1 N/C due East

b)Again using the same formula

E = 30 x 10^-6 N/-30 x 10^-6 = -1 N/C

Hence, E = 1 N/C due East

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