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Q Safari File Edit View History Bookmarks Window Help 8% C Mon 11:24 PM edugen.wileyplus.com Chegg Study Guided Solutions and Study Help | Chegg.com WileyPLUS WileyPLUS: MyWileyPLUSI Help I Contact Us I Log Out Cutnell, Physics, 10e General Physics 1 (Fall 2017) (APHY105) Home Read, Study & Practice Assignment Gradebook ORION Downloadable eTextbook Assignment> Open Assignment ON BACK NEXT ASSIGNMENT RESOURCES Homework 6 (Chapter Chapter 04, Problem 039 A 62.7-kg crate rests on a level floor at a shipping dock. The coefficients of static and kinetic friction are 0.702 and 0.306, respectively. What horizontal pushing force is Chapter 04 Problem Chapter 04, Problem hapter 04, Problem required to (a) just start the crate moving and (b) slide the crate across the dock at a constant speed? (a) Number (b) Number Click if you would like to Show Work for this question: 016 GO Units Units Chapter 04, Problem 057 Chapter 04 Problem 076 Chapter 04, Problem 074 SHOW HINT Chapter 04 Problem 064 GO LINK TO TEXT LINK TO TEXT Review Score Objective By accessing this Question Assistance, you will learn while you earn points based on the Point Potential Policy set by your instructor Question Attempts: 0 of 4 used SAVE FOR LATER SUBMIT ANSWER Earn Maximum Points available only if you answer this question correctly in three attempts or less.Explanation / Answer
along vertical
Fnet = 0
n - mg = 0
n = normal force
n = mg
along horizontal
Fx = fs
fs = maximum static frictional force = us*n
Fx = 0.702*62.7*9.8 = 431 N <<<<-------ANSWER
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part (b)
when the crate moves with constan speed
acceleration ax = 0
Fnet = Fx -fk
from newtons second law
Fnet = m*ax
Fx - fk = 0
Fx = fk = uk*n = 0.306*62.7*9.8 = 188 N <<<--ANSWER
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