A chair of weight 105 N lies atop a horizontal floor; the floor is not frictionl

Question

A chair of weight 105 N lies atop a horizontal floor; the floor is not frictionless. You push on the chair with a force of F = 45.0 N directed at an angle of 37.0 below the horizontal and the chair slides along the floor.

Part A

Using Newton's laws, calculate n, the magnitude of the normal force that the floor exerts on the chair.

A chair of weight 105 N lies atop a horizontal floor; the floor is not frictionless. You push on the chair with a force of F = 45.0 N directed at an angle of 37.0 below the horizontal and the chair slides along the floor.

Part A

Using Newton's laws, calculate n, the magnitude of the normal force that the floor exerts on the chair.

Explanation / Answer

Here, for the normal force

let the normal acting is N

Now, in the vertical direction

as the acceleration is zero

105 + 45 * sin(37 degree) - N = 0

solving for N

N = 132.1 N

the normal force is 132.1 N

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