Jack tries to toss his baseball up onto the roof of a garage. At the instant whe

Question

Jack tries to toss his baseball up onto the roof of a garage. At the instant when the ball leaves Jack's hand, the ball is traveling with a velocity of 9.00 m/s directed 70.0 degrees above the horizontal. At this instant, the ball is located 1.00 m above the ground, 2.00 m below the level of the garage roof, and at a horizontal distance of 4.00 m from the near wall of the garage, as shown in the figure. +X 2.00 m 70.00 Assume that air resistance is negligible, although it would not be so here. 1.00 m 4.00 m

Explanation / Answer

in vertical, y = v0y t + ay t^2 / 2

2 = (9 sin70)t - 9.81 t^2 / 2

t = 1.44 sec

d = (9 cos70)(1.44) = 4.43 m

6 (a) at a horzontal distance of 0.43 m from its launch.

7. vfy = (9 sin70) - (9.81 x 1.44) = - 5.67 m/s

vfx = v0x = 9 cos70 = 3.08 m/s

v = sqrt(vfx^2 + vfy^2) = 6.45 m/s

Ans(d)

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