Problem 29.26 - Enhanced - with Feedback Part A A proton moves in the magnetic f

Question

Problem 29.26 - Enhanced - with Feedback Part A A proton moves in the magnetic field B0.56i T with a speed of 1.1*10 m/s in the directions shown in the figure. (Figure 1) In Figure (a), what is the magnetic force F on the proton? Give your answers in component form Express vector F in the form of Fr, Fy, Fz , where the x, y, and z components are separated by commas You may want to review (LD pages 815-820) Submit My Answers Give Up Part B In Figure (b), what is the magnetic force F on the proton? Give your answers in component form Express vector F in the form of Fr, Fy, Fz , where the x, y, and z components are separated by commas Figure 1 of 1 Submit My Answers Give Up (a) z (b) z Continue 45°

Explanation / Answer

Given,

B = 0.56 i T ; v = 1.1 x 10^7 m/s

A)We know that the magnetic force on a moving charge is given by:

F = q (v x B)

F = q v B sin(theta)

F = 1.6 x 10^-19 x 1.1 x 10^7 x 0.56 x sin45 = 6.97 x 10^-13 N

Hence, F = 6.97 x 10^-13 N

b)In case B, theta = 90 deg

F = q v B sin90 = q v B

F = 1.6 x 10^-19 x 1.1 x 10^7 x 0.56 = 9.86 x 10^-13 N

Hence, F = 9.86 x 10^-13 N

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