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Chrome File Edit View History Bookmarks People Window Help 99% · Thu 11:39 PM u.s. G Ahmad 830 USD to SAR-Google Sea Secure l https://edugenwileyplus.com/edugen/student/mainfr.uni WileyPLUSDifferential calculus. X-LA University of South Alabama : x{ LA MA 238-102-Model Test 2 × WileyPLUS University of South D Apple iCloud Yahoo Bing W wikipedia R Facebook y Twitter The Weather Channel Yelp > Other Bookmarks WlleyPLUS: MyWlleyPLUS | Help | Contact Us I Log Out Calculus-based Physics I & II (PH 201-202) Apps LinkedIn WileyPLUS Halliday, Fundamentals of Physics, 10,e Home Read, Study&Practice; Gradebook ORION Downloadable eTextbook Assignment > open Assignment FULL SCREEN PRINTER VERSION BACK ASSIGNMENT RESOURCES Chapter 16, Problem 052 A rope, under a tension of 104 N and fixed at both ends, oscillates in a second-harmonic standing wave pattern. The displacement of the rope is given by y= (0.116m)sin(TX / 4.00)sin(11.Ont) where x = 0 at one end of the rope, X is in meters, and is in seconds. What are (a) the length of the rope, (b) the speed of the waves on the rope, and (c) the mass of the rope? (d) If the rope oscillates in a third-harmonic standing wave pattern, what will be the period of oscillation? (a) Number (b) Number (c) Number (d) Number 201-21 014 016 042 Units Units Review Units Units LINK TO TEXT Question Attempts: 0 of 6 used SAVE FOR LATER SUBMIT ANSWER httos:/fedugenwleyplus.com/edugen/shared/assignment/test/ag istuni?id-asnmt210075 9

Explanation / Answer

a) y = 0.116 sin (pi x / 4) sin (11 pi t)

w = 2 pi f

11 pi = 2 pi f

f = 5.5 hz

pi / 4 = 2 pi / lambda

lambda = 8 m

lambda = 2 L / n

L = n * lambda / 2 = 2 * 8 / 2

length of rope L = 8 m

b) v = f * lambda = 5.5 * 8 = 44 m/s

c) v = sqrt [T / (m/L)]

44 = sqrt [104 / (m/8)]

m = 0.429 kg

d) f = n (v / 2 L) = 3 (44 / 2 * 8) = 8.25

T = 1/f = 1/8.25

period of oscillation = 0.12 s

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