UESTIONS 5 & 6: Refer to Figure 1, which shows several equipotential surfaces. +

Question

UESTIONS 5 & 6: Refer to Figure 1, which shows several equipotential surfaces. +800v 5. An electron initially at rest is released at point B. The electron would A. move toward the left. B. remain stationary C. move to the right. D. oscillate left-to-right in SHM. E. There is not enough informationto +1000v +600 v +400 v tell Figure 1 6. An electron and proton both begin at A and move to D. As they move, A. both gain potential energy B. both lose potential energy C. the electron gains potential energy while the proton loses it. D. the electron gains loses energy while the proton gains it.

Explanation / Answer

5. Direction of electric field is from higher potential to lower potential so here in this case it will be from left to right and electron is negatively charged particle so it will experience electrostatic force in the direction opposite to the direction of field so it willove towards left. So option A is correct.

6. Change in potential energy = qV

So for electron potential energy will increase whereas for protiom potential energy will decrease.

So electron gains potential energy while the proton loses it.

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