As shown in the figure below, cars #1 and #2 are sliding acces a horizontal fric

Question

As shown in the figure below, cars #1 and #2 are sliding acces a horizontal frictionless surface. The cars are equipped with a coupling arrangement similar to the one on railroad cars. Car #1 overtakes car #2 and they have a totally inelastic collision and become coupled together. You know the mass of each car; m 12.0 kg and m2 50.0 kg. In addition, you are provided with the following graph, which shows the momentum of car #1 before, during and after the collision. Determine the velocity of car #2 before the collision. m/s -c p(kg m/s) 100 40 t (s)

Explanation / Answer

m1 = 12 Kg

m2 = 50 Kg

momentum initial of car 1 = 100 kg m/s

momentum final of car 1 = 40 kg m/s

So initial velocity of car 1 = 100/12 = 8.33 m/s

final velocity of car 1 = 40/12 = 3.33 m/s

Velocity of car 1 after collision = 3.33m/s

As they couple together, Velocity of car 2 after collision = 3.33 m/s

Momentum of car 2 after collision = 3.33 x 50 = 166.67 Kg m/s

By conservation of momentum

100 + 50v2i = 40 + 50 x 3.33

=> v2i = 2.13 m/s

So velocity of car 2 before collision = 2.13 m/s

Please rate my answer....

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.