In this problem, we will consider the following situation as depicted in the dia

Question

In this problem, we will consider the following situation as depicted in the diagram: (Figure 1) A block of mass m slides at a speed v along a horizontal smooth table. It next slides down a smooth ramp, descending a height h, and then slides along a horizontal rough floor, stopping eventually. Assume that the block slides slowly enough so that it does not lose contact with the supporting surfaces (table, ramp, or floor). You will analyze the motion of the block at different moments using the law of conservation of energy.Which form of the law of conservation of energy describes the motion of the block when it slides from the top of the table to the bottom of the ramp?

Explanation / Answer

The Block comes to stop when Potential energy is zero

i.e. U = 0. So Energy lost due to friction is

E = 0.5mv2 + mgh (answer)

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