Problem 10.71 Part A If the ball is released from rest at a height of 0.69 m abo

Question

Problem 10.71 Part A If the ball is released from rest at a height of 0.69 m above the bottom of the track on the no-slip side, what is its angular speed when it is on the frictionless side of the track? Assume the ball s a solid sphere of radius 3.0 cm and mass 0.14 kg (Eigure.1) Express your answer using two significant figures rad/s Submit My Answers Give Up Foure 1 of 1 Part B How high does the ball rise on te fricionless side? Express your answer using two significant figures in reen Bubmit My Answers Give e Noslip Prictionless Screen

Explanation / Answer

A] potential energy = KE

mgh = 0.5 mv^2 + 0.5iw^2 where w = v/r and i=2/5 mr^2

mgh = 0.7 mv^2

v = sqrt(gh/0.7) = sqrt(9.8*0.69/0.7) = 3.108 m/s

w = v/r = 3.108/0.03 = 103.6 rad/s

in two sig fig w = 1.0*10^2 rad/s answer

B] The translational KE will be converted to potential energy

h = v^2/2g = 3.108^2/[2*9.8] = 0.49 m answer

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