Exercise 27.21 Part A Find the speed of the deuteron. A deuteron (the nucleus of

Question

Exercise 27.21 Part A Find the speed of the deuteron. A deuteron (the nucleus of an isotope of hydrogen) has a mass of 3.34 102 kg and a charge of 1.60 10-10 C. The deuteron travels in a circular path with a radius of 6.80 mm in a magnetic field witha magnitude of 3.00 T 8.3 105 m/s Submit My Answers Give Up Incorrect; Try Again; 5 attempts remaining Part B Find the time required for it to make of a revolution. Submit My Answers Give Up Part C Through what potential difference would the deuteron have to be accelerated to acquire this speed?

Explanation / Answer

Part A:

mv2/r = qvB

v = qBr/m = (1.6*10-19*3*0.0068)/3.34*10-27=977245.51 m/s

Part B:

speed = 977245.51 m/s

radius = 6.8 mm = 0.0068 m

time period = (2*pi*0.0068/977245.51)=4.372*10-8 second

time required for 1/2 revolution = 4.372*10-8/2=2.186*10-8 s

Part C:

kinetic energy of deuteron = 0.5*3.34*10-27*977245.512=1.595*10-15 Joule

let the potential difference = V

qV=1.595*10-15

1.6*10-19*V = 1.595*10-15

v = 9967.9 volts

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