Problem 23.41 Part A As shown in (Figure 1), a layer of water covers a slab of m

ID: 1780939 • Letter: P

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Problem 23.41 Part A As shown in (Figure 1), a layer of water covers a slab of material X in a beaker. A ray of light traveling upward follows the path indicated Assume that 1-48- and 2 = 64° Using the information on the figure, find the index of refraction of material X Express your answer using three significant figures Submit My Answers Give Up Part B Figure 1 of 1 Using the information on the figure, find the angle the light makes with the normal in the air Express your answer in degrees to two significant figures ir Water Submit My Answers Give Up Provide Feedba

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Problem 23.41)

A)1.33 x sin48° = n x sin(90-64)

n = 2.25

B) 1.33 x sin48° = 1 x sin(theta)

Theta = sin-1(1.33 x sin48°) = 81.26°

Problem 23.39)

Bi = tan-1(2.00/1.80) = 48.013 degrees

Snell's law:

ni sin(Bi) = nr sin(Br)

(1.00) sin(48.01) = 1.333 sin(Br)

==> Br = 33.98 degrees

We have:

x = 2.50 tan(33.98) = 1.68 m

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Problem 23.41 Part A As shown in (Figure 1), a layer of water covers a slab of m

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