(8e27p22) A solar cell generates a potential difference of 0.1015 V when a 500 r

Question

(8e27p22) A solar cell generates a potential difference of 0.1015 V when a 500 resistor is connected across it, and a potential difference of 0.1553 V when a 1000 resistor is substituted. What is the internal resistance of the solar cell? 0.000203 V Submit Answer Incompatible units. No conversion found between "v" and the required units.Tries 0/10 Previous Tries What is the emf of the solar cell? Submit Answer Tries 0/10 The area of the cell is 5.0 cm2, and the rate per unit area at which it receives energy from light is 2.0m W/ cm2. What is the efficiency of the cell for converting the light energy to thermal energy in the 1000 external resistor? (percent-Do not enter a unit) Submit Answer Tries 0/10

Explanation / Answer

E=emf

r=internal resisitance

E-i*r=v

E-(0.1015/500)*r=0.1015v

E-(0.1553/1000)*r=0.1553v

so,(-1.553*10^-04+2.03*10^-04)*r=0.1553-0.1015

r=0.0538/4.77*10^-05=112

r=112 resistance.

now emf,0.1553+(1.553*10^-04)*112=0.172v

0.1015+(2.03*10^-04)*112=0.124v

p dissipated po=v^2/r=0.1553^2/1000=2.41*10^-05W

and p receive pi=2.0*10^-03v/cm^2*5cm^2=1.0*10^-02W

efficency=po/pi=2.41*10^-05/1.0*10^-02

=0.241%.

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