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Safari File Edit View History Bookmarks Window Help 4898% EMon 1:06 AM aE use11fl.theexpertta.com Netflix Zumba Social The Expert TA | Human-like Grading, Automated! Class Management I Help HW 12 Begin Date: 10/30/2017 11:00:00 AM Due Date: 11/13/2017 11:00:00 AM End Date: 11/13/2017 11:00:00 AM (10%) Problem 8: A cart is moving along and very close to a level air track at a speed of 0.48 m/s. The surface area of the cart's underside is 2.8 x 10-2 m2 and the thickness of the air layer between the cart and the track is 6.2 x 10-5 m. The air temperature is 20°C Assignment Status Click here for detailed view 50% Part (a) Find the magnitude of the retarding force in newtons, acting on the cart due to the viscosity of the air layer between the cart and the air track. Take the viscosity of air at the given temperature to be 1.81 x 10-5 Pas. Grade Summary Deductions Potential 100% Problem Status Completed Completed Completed Completed Attempts remaining: S 5% per attempt) detailed view cotan asin0acos0 atan acotanO sinhO coshO tanh0 cotanhO Degrees Radians 3 A 6 0 END 6 Completed i) Partial Submit Hint I give up! Completed | Partial Hints: 1% deduction per hint. Hints remaining: 2 Feedback: 1% deduction per feedback. 10 - 50% Part (b) What is the ratio of this force to the weight of the 0.31 kg cart? All conteat 2017 Expent TA, LLC 13

Explanation / Answer

We know

Force/Area=viscosity*velocity/thickness

We got force=3.92*10(-3)N

(b) weight=0.31*9.8

Ratio=949.1:1

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