Not Charging 8:06 PM edugen.wieyplus..com .11 Verizon Cutnell, Physics, 10e COLL

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Not Charging 8:06 PM edugen.wieyplus..com .11 Verizon Cutnell, Physics, 10e COLLEGE PHYSICS ( ice Assignment Gradebook ORION Downloadable eTextbook ent FULL SCREEN PRINTER VERSION BACK NEXT Chapter 10, Problem 09 In 0.646 s, a 7.09-kg block is pulled through a distance of 3.50 m on a frictionless horizontal surface, starting from rest. The block has a constant acceleration and is pulled by means of a horizontal spring that is attached to the block. The spring constant of the spring is 415 N/m. By how much does the spring stretch? Number Units the tolerance is +/-2% LINK TO TEXT Question Attempts: 0 of 6 used SAVE FOR LATERSUBIT ANSWER

Explanation / Answer

The acceleration of the block can be determined from:

d = u*t + a*t^2/2

where, u is initial velocity which is zero

d = a*t^2/2

a = 2d/t^2

= 2*3.50/(0.646)^2

= 16.77 m/s^2

The force applied F = m*a

F = 7.09*16.77 = 119 N

Since the force of a spring F = k*x

where, x is elongation,

k is spring constant

x = F/k

= 119/415 = 0.286 m

Answer

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