using the wavelengths given in the figure, compute the energy difference E betwe

Question

using the wavelengths given in the figure, compute the energy difference E between the 1s14p1 and 1s13p1 singlet (S = 0) states in helium. Repeat the calculation for the 3d and 4d triplet (S 1) states. (Give your answer to four decimal places.) ev ev 1.144 114 1.14p 1s 3s -2 -3 1s12p1 1s12s -5 -6 -24 -25 1s2 Compare this energy difference with the value expected using the Bohr model, assuming that the p electron is screened by the s electron. Results agree very well because the 4p and 4d electrons are screened by the 1s electron

Explanation / Answer

solution:

dE (4p- 3p) =-(501.6-396.5) =-105.1 eV

dE(4d-3d) =-(447.1-587.6) =-140.5eV

Ebohr =.0529*N2/Z

Z=1 for helium

dEbohr =(.0529/Z)*(N12-N22) put the value of N and you can find the remaining answer

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