11] Moving charged particles are released with a velocity (details listed below)

Question

11] Moving charged particles are released with a velocity (details listed below) at the point P (2 m, 2 m) in a large region of space which has a uniform magnetic field in the +x direction. All these particles have the same mass, and they are released individually into this field. Rank from greatest to least the change in kinetic energy of these charged particles after they have traveled 1 cm from P. (5 pts.) Case Charge Speed Direction 5 mC 5 mC 5 mC 5 mC 10 mC +10 mC 10 mC +10 mC 3 m/s 3 m/s 3 m/s 3 m/s 3 m/s 3 m/s 5 m/s 5 m/s tx P (2,2) Greatest 1 Least Or, the change in kinetic energy will be the same for all of these (but not zero) Or, the change in kinetic energy will be zero for all of these

Explanation / Answer

F=q(v x B), If charged particle is moving along +x axis angle between v and B will be zero hence magnetc force will be zero and in turn work done will be zero by magnetic field.

If particle is moving along +y axis that is perpendicular to magnetic field, velocity v remains perpendicul to force hence again work done is zero by magnetic field. So total work done on the particle is zero.

Now since according to work- energy theorem, W=K

Therefore change in kinetic energy, K = 0 in all the eight cases.

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