Please help with a-b. Thanks (17%) Problem 5: Two capacitors of capacitance 3C a

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Please help with a-b. Thanks

(17%) Problem 5: Two capacitors of capacitance 3C and 5C (where C-0.12 F) are 6.5 . connected in series with a resistor of resistance R Randomized Variables R=6.5 3C 5C C=0.12F ©theexpertta.com 50% Part (a) How long will it take the amount of charge in the circuit to drop by 75% in seconds? Grade Summa Deductions Potential ry 090 100% sin0 cotan0asin acos0 atan0 acotan sinhO cosh0 tanh cotanh0 cos) Submissions Attempts remaining: 20 (000 per attempt) detailed view tan *12 3 END Degrees Radians NO CLEAR Submit Hint I give up! Hints: 0% deduction per hint. Hints remaining:-- Feedback: 0% deduction per feedback. 50% Part (b) If the circuit was charged by a 10.0 V source how much total charge (in C) did both capacitors have in them to begin with?

Explanation / Answer

a) Cequ = c1 * c2 / c1 + c2 = (3C * 5C) / (8 C)

= 15 C2 / 8C = 1.875 * C = 1.875 * 0.12

Cequ = 0.225 F

time constant T = R Cequ = 6.5 * 0.225 = 1.46 s

e-t/1.46 = (1 - 0.75)

t/1.46 = 1.386

t = 2.02 s

b) Q = C V = 0.225 * 10

total charge = 2.25 C

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