Problems., Support each answer with detailed reasoning for full credit. Do NOT r

Question

Problems., Support each answer with detailed reasoning for full credit. Do NOT regurgitate memorized results from problems worked in the text or recitation. Any answers NOT recorded on the Scantron answer page will NOT be counted The uniform magnetic field B in the diagram has a magnitude of 65 T and a direction of 55 degrees with respect to the y-axis. A proton is traveling parallel to the y-axis at a velocity of 5.0 x 107 m/s. 17. What is the angle between the velocity and the magnetic field? 05 5° C) 55 D)90 E) 180 A)0° 18. What is the magnitude of the magnetic force on the proton? N-1.88 × 10-n N B)2.24 x 10-11 N C)3.15x10"o NO4.26 × 10-30 N K) 5.79 x 10"N 19. What is the direction of the magnetic force on the proton? A) right B) left C)up D) down E) into the page out of the pauge

Explanation / Answer

17)The angle with y axis is:

alpha = 55 deg

Since the proton is moving with velocity parallel to y axis. The angle between B and v will be:

(C)theta = 55 deg

18)The magnitude of magnetic force will be:

F = q v B sin(theta)

F = 1.6 x 10^-19 x 5 x 10^7 x 65 x sin55 = 4.26 x 10^-10 N

Hence, (D)F = 4.26 x 10^-10 N

19)B force is always perpendicular to both B and v. So the direction will be:

(F)Out of the page

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