Static Equilibrium - Horizontal Plank A uniform plank of length L is supported b

Question

Static Equilibrium - Horizontal Plank A uniform plank of length L is supported by two equal forces, Px at X-0 and Fy at Y-L. The support at X is then moved to Z which is ¼ of the w ay from the left end to the right end, and the torce at Z is Fz. Note that Fy changes in the move of the X support to Z, but you only use the values Fx before the move and Fz after the move. (5) (10 points) What is the numerical value of the ratio (force at X) / (force at Z)? The numerical value of the ratio ( FX / Fz) Cosel

Explanation / Answer

consider the rotation axis is passing through center of the plank and perpendicular to it's length

then Net torque acting about the axis is zero

(-Fx*L/2) + (Fy*L/2) =0

Fx = Fy

now for Fz

then Net torque acting about the same axis is zero

(-Fz*L/4)+(Fy*L/2) = 0

Fz/2 = Fy

Fz = 2*Fy

Fx/Fz = Fy/(2*Fy) = 1/2

Related Questions

Navigate

• Browse (All)
• Browse S
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.