« previous 11 of 11 | return to assignment Full Solution Ch27 Part A A hydrogen
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« previous 11 of 11 | return to assignment Full Solution Ch27 Part A A hydrogen gas tube has a 11.5 V potential difference across it. In this problem, you will utlimately find the shortest wavelength of light that it can emit. Follow the steps below to get full credit. Assume that all hydrogen atoms are initially in the ground state, which is justified if the atoms are at room temperature +1 Sketch and translate: Draw and label a sketch of the initial, intermediate, and final states of importance Include things in your sketch that help explain the mechanism behind the discharge tube's glow, as shown in Example 27.3 (or my version of it in lecture). Arrange these three sketches across the page horizontally so that you can do the next step underneath each one +1 Simplify and Diagram: Draw an energy bar graph for each of the three state. Label the energies of importance in each state. After you've determined some quantities (next two steps), come back to this diagram and label the actual amount of energy (in Joules or eV) for each bar that you ve drawn +1 Represent mathematically: Write the mathematical description of the bar graphs (e.g. including the specific energy terms like 1/2 mv*2 for kinetic energy). +1 Solve & evaluate for n: Use your work so far to determine the maximum emission line that could be emitted by the hydrogen gas in this gas discharge tube with an 11.5 V potential difference. You can check your answer in part A. +1 Solve & evaluate for wavelength: Determine what the wavelength of this emission line is. +1 Evaluate (again): Determine the quantitative values for the energy levels in your bar graph and label the actual amount (in Joules or eV --whichever is more convenient, but be consistent). Check to make sure that the size of the bars scale appropriately with the values you determined. Find the maximum emission line that could be emitted by hydrogen gas in a gas discharge tube with an 11.5-V potential difference across it. Express your answer as an integer Submit My Answers Give Up Part B This question will be shown after you complete previous question(s). ContinueExplanation / Answer
given q = 11.5 eV
using E = dV X q
= 11.5 X 1.6 X 10-19 J
E = 1.84 X 10-18 J
using the equation for energy is " E "
E = 13.6 / n2
n2 = 13.6 / 1.84
n2 = 7.391
n = 2.71
n = 2
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