In a Show Question Details here is a uniform magnetic field with a magnitude of

Question

In a Show Question Details here is a uniform magnetic field with a magnitude of 2.00 T. You take a particle with a charge of +9.00 x 106 C, and give it an initial speed of 1.40 x 10 m/s in this field. Assume that, after you release it, the particle is influenced only by the magnetic field (a) Under these conditions, what is the maximum possible magnitude of the magnetic force experienced by the particle? (b) Under these conditions, what is the mimimum possible magnitude of the magnetic force experienced by the particle? c f the particle experiences a orce with a magnitude that is 20.0% of the magnitude of the maximum force what s the angle between the art cle's velocity and the magnetic field? Use an angle between 0° and 90.

Explanation / Answer

magnitude of magnetic force Fb = q*v*B*sintheta

(a)

for maximum force sintheta should be maximum

maximum value of sintheta = 1

Fbmax = q*v*B*1 = 9*10^-6*1.4*10^5*2 = 2.52 N

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(b)

for minimum force sintheta should be minimum

maximum value of sintheta = 0

Fbmin = q*v*B*0 = 0

=--------------------

(c)

Fb = q*v*B*sintheta

given Fb = 20% of Fbmax = (20/100)*2.52 = 0.504 N

0.504 = 9*10^-6*1.4*10^5*2*sintheta

sintheta = 0.2

theta = sin^-1(0.2) = 11.54 degrees <<<----ANSWER

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