3. 0/1 points| Previous Answers OSColPhys2016 8.4.WA.033. My Notes Ask Your Teac

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3. 0/1 points| Previous Answers OSColPhys2016 8.4.WA.033. My Notes Ask Your Teache Two ice pucks (one orange and one blue) of equal mass are involved in a perfectly elastic glancing collision as shown in the figure below. The orange puck is initially moving to the right at Vol = 5.15 m/s, strikes the initially stationary blue puck, and moves off in a direction that makes an angle of 36.0° with the horizontal axis while the blue puck makes an angle of = 54.0 with this axis as in figure b). Note that for an elastic collision of two equal masses, the separation angle + = 90.0°. Determine the speed of each puck after the collision. 2.42 of Establish an appropriate coordinate system and sign convention and convince yourself that momentum is conserved in the collision. See if you can write a statement of conservation of momentum = in the x and y directions and then solve these two equations simultaneously for the final speed of the two pucks. All of our work will be made more straightforward by the fact that the two pucks have the same mass-be sure to cancel out the mass. m/s 1.75 Vbr Establish an appropriate coordinate system and sign convention and convince yourself that momentum is conserved in the collision. See if you can write a statement of conservation of momentum = in the x and y directions and then solve these two equations simultaneously or the ina speed of the two puck All of our work will emade more strag forward the at a the opucks have the same mass-be sure to cancel out the mass. m/s Vov Before collision After collision Additional Materials Reading

Explanation / Answer

m1v1 = m1v1' + m2v2 (conservation of momentum); however since m1 = m2
v1 = v1' + v2 (where v are vectors, not scalars)

Therefore
Vo = Vo'*cos(th) + Vb*cos(ph), (x direction) and
Vo'*sin(th) = Vb*sin (ph) or Vb = Vo'* (sin(th)/sin(ph)) (y direction; basically the two vertical vectors must cancel one another out since the original vector had no vertical vector component)
Substituting
Vo = Vo'*cos(th) + Vo'* (sin(th)/sin(ph))*cos(ph)
5.15m/s = Vo'*(cos36° + sin36°/tan54°), or
Vo' = 4.17 m/s
Vb = 4.17m/s*(sin36°/sin54°) = 3.03 m/s

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