O The horizontal components of both the velocity and acceleration are zero 3 of

Question

O The horizontal components of both the velocity and acceleration are zero 3 of 3 attempts used Question 9 A cannon sitting on level ground is aimed at 45.0 degrees relative to the horizontal. It fires a test shot at a target located 100.0 meters away from the cannon on the same level ground. The test overspoots the target by 20.0 meters. Which of the following angles can the cannon be adjusted to to hit the target. You may heglect air resistance and assume the cannon always delivers the same initial velocity to the cannonball O 49.1 deg

Explanation / Answer

along vertical

displacement y = 0

acceleration ay = -g

time = t

y = voy*t + (1/2)*ay*t2

0 = v*sintheta*t - (1/2)*g*t^2

t = 2*v*sintheta/g

along horizontal

x = vox*t

x = v*costheta*2*v*sintheta/g

x = v^2*sin(2theta)/g

for x = 120 m

theta = 45

120 = v^2*sin(2*45)/g

v^2 = 120*g

the cannon is projected with same but at different angle to reach target at 100 m

for x = 100

theta =?

100 = 120*g*sin(2theta)/g

100 = 120*sin(2theta)

sin(2theta) = 100/120

2theta = 56.4

theta = 56.4/2

theta = 28.2 degrees

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