PHYS- Quz a In 2009, Mac Bennen recorded a standing vertical jump of 0.86 mthe c

Question

PHYS- Quz a In 2009, Mac Bennen recorded a standing vertical jump of 0.86 mthe curem recond ventical jyomp forhok player. When he set the recond, Bennett's mass wa80 kg 1 Calculate w, Mac Bennett's weight when he set record. 2. Calculate vo, the speed at which Bennett left the floor 3, Calculate i·the time that Bennett was above the noor before reaching his record-setting altitude. If Mac Bennett's jumping motion required 0.501 seconds, then calculate his acceleration a while he was in contact with the floor. 4. 5. Calculate n, the normal force exerted by the floor on Bennett during his jumping motion.

Explanation / Answer

1) Weight w = mg = (80)(9.81) = 784.8N

2) At the highest pt. (0.86m), v = 0.

Using:

v^2 = u^2 + 2ay

where, v->final velocity = 0

u -> initial velocity = ?

a = acceleration = -g = -9.81m/s2

y-> vertical displacement = 0.86m

so:

0 = u^2 + 2(-9.81)(0.86)

=> u = 4.11m/s2

3) Using: v = u + at

=> t = (v-u)/a = (0-4.11)/(-9.81) = 0.4187s

4) If t = 0.501s, then:

a = (v-u)/t = (0-4.11)/0.501 = -8.2m/s2

So, a(floor) + (-9.81) = -8.2

=> a(floor) = 1.61 m/s2

5) Using Newtom's 2nd law of motion:

If condition of (4) is to be considered:

N - w = ma

=> N = w + ma = mg + ma = m(g+a) = 80(9.81+1.61) = 913.33N

If initial condition is to be considered:

N = w = 784.8N

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