Problem 32.59 Part A A proton moving in a uniform magnetic field with L1.27 x 10

Question

Problem 32.59 Part A A proton moving in a uniform magnetic field with L1.27 x 106 i m/s experiences force F1 = 1.76 × 10-16 k N. A second proton with a 2.21 × 106 J m/s experiences F2 :--3.94 × 10 16 k N in the same field What is the magnitude of B? Express your answer with the appropriate units BV Units atue Submit My Answers Give Up Part B What is the direction of B? Give your answer as an angle measured ccw from the +x-axis Express your answer with the appropriate units atue Units Submit My Answers Give Up ide Feedback Continue

Explanation / Answer

a) F = q v * B

1.76 * 10-16 = 1.6 * 10-19 * 1.27 * 106 * B1

B1 = 8.66 * 10-4 T

3.94 * 10-16 = 1.6 * 10-19 * 2.21 * 106 * B2

B2 = 1.11 * 10-3 T

magnitude = sqrt [(8.66 * 10-4)2 + (1.11 * 10-3)2]

= 1.41 * 10-3 T

b) theta = tan-1 [1.11 * 10-3 / 8.66 * 10-4]

= 52 deg

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