1.37Tu0 3 10/20/2017 05:36 PM -Print | Calculator Periodic Table Gradebook Quest

Question

1.37Tu0 3 10/20/2017 05:36 PM -Print | Calculator Periodic Table Gradebook Question 7 of 20 Sapling Learning A piece of luggage is being loaded onto an airplane by way of an inclined conveyor belt. The bag, which has a mass of 15.0 kg, travels 2.50 m up the conveyor belt at a constant speed without slipping. If the conveyor belt is inclined at a 30.0° angle, calculate the work done on the bag by: the force of gravity (Wg) the normal force (W) the friction force (Wi) the conveyor belt (Wconveyor) the net force (Whet) 2.50 m 30.0° 368 J 184 J -368 J -184 J Zero 319 J -319 J net conveyo Exit is e Check Answer e Next Rp

Explanation / Answer

Workdone by gravity Wg = -mg sin×l= -15×9.8×Sin30×2.5=-183.75 Joule

The normal force is perpendicular to displacement. So workdone by normal force is zero.

Workdone by friction force=mg Sin *l=183.75J

Workdone by conveyor belt is equal to workdone by friction.

Workdone by all forces is equal to change in kinetic energy. Here speed is constant.So change in k.e is zero. So workdone by all forces is equal to zero.

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