W25Exercise 25.4 previo Exercise 25.4 An 18-gauge copper wire (diameter 1.02 mm)

Question

W25Exercise 25.4 previo Exercise 25.4 An 18-gauge copper wire (diameter 1.02 mm) carries a current with a current density of 2.90 × 106 A/m2 . The density of free electrons for copper is 8.5 × 1028 electrons per cubic meter. != 10.8 Submit My Answers Give Up Incorrect; Try Again; 2 attempts remaining Part B Calculate the magnitude of the drift velocity of electrons in the wire. Express your answer with the appropriate units. LA 2.96 10-5 m Vd = Submit My Answers Give Ujp Incorrect; Try Again; 8 attempts remaining Classic snake fi

Explanation / Answer

Given

Part A

current density J = I/A = 2.9*10^6 A/m2

so the current in the wire is I = J*A

I = J*pi*r^2

I = 2.9*10^6 *pi*(0.51*10^-3)^2 A

I = 2.36967 m

ParB

drift speed is Vd = J/n*e

Vd = 2.9*10^6 /(8.5*10^28*1.6*10^-19) m/s

Vd = 0.0002132353 m/s

Vd = 21.32353*10^-5 m/s

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