A proton, moving with a velocity of the initially moving proton is 1.90 times th

Question

A proton, moving with a velocity of the initially moving proton is 1.90 times the speed of the proton initialy at rest, find the following i, collides elastically with another proton that is initially at rest. Assuming that after the (a) the speed of each proton after the collision in terms of v initially moving protorn initially at rest proton the of (o) the drection af the velocity vectors after the cn(essme tht the intaily moving proton scatters tomerd the posatve y drection) irvitially moving proton ° relative to the +x direction relative to the**direction initially at rest proton

Explanation / Answer

a)

By Conservation of momentum

(1/2)mpVi2=(1/2)mpV12+(1/2)mpV22

Given V1=1.9V2

=>(1/2)mpVi2=(1/2)mp(1.9V2)2+(1/2)mpV22

Vi2=4.61V22

V2=0.4657Vi(initially at rest proton)

V1=1.9*0.4657Vi=0.8848Vi(initially moving proton)

b)

Initial moving proton

o1=tan-1(0.8848)=41.50

initially at rest proton

o2=tan-1(0.4657/0)=90o

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