A 18.5-1b block rests on the floor (a) What force does the floor exert on the bl

Question

A 18.5-1b block rests on the floor (a) What force does the floor exert on the block? magnitude directionSelect- lb (b) If a rope is tied to the block and run vertically over a pulley, and the other end is attached to a free-hanging 11.5-lb weight, what is the force exerted by the floor on the 18.5-ID block? magnitude direction Select- (c) If we replace the 11.5-lb weight in part (b) with a 30.5-lb weight, what is the force exerted by the floor on the 18.5-lb block? magnitude direction | Select Need Help? .neari Submit Answer Save Progress Practice Another Version 10 points SerPOP54.P.022.wi. The systems shown below are in equilibrium with m 6.10 kg and 33.0 the spring scales are calibrated in newtons, what do they read? I nore the masses o the pulleys and strings and assume the pulleys and the incline are frictionless. scale in (a): scale in (b): scale in (c): scale in (d);

Explanation / Answer

a)

1 lb =0.453592 kg

since the block is at rest on horizontal floor ,the gravitational force is balanced by normal force

FN=Fg=mg =(18.5*0.453592)*9.81=82.32 N

Its direction is upward

b)

Force acting on the free hanginf block

T=(11.5*0.453592)*9.81=51.17 N

force exerted on the block

FN=82.32-51.17=31.15 N

Direction is upward

c)

since free hanging weight is heavier than the block ,the block will be lifted up the floor and there will ne no contact.

Therefore

FN=0

No direction

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