\"Active Figure 4.13 Pushing Blocks With A Constant Force In the simulation belo

Question

"Active Figure 4.13 Pushing Blocks With A Constant Force

In the simulation below, you can observe the effects of a force applied to a two-block system.

Instructions: Use the direction toggle (dir'n) to set the direction of the external force, and click start to apply the force.

Push the direction toggle so the direction arrow points in the positive direction. Is this direction to your left or to the right? Also, before proceeding, reset the positions of the two masses to zero.

Start the simulation and observe the masses, as they accelerate to the right on a frictionless surface and eventually disappear off the screen.

Observe the on-screen values of time, distance and force and notice that the force remains constant throughout the motion.

Record the final values of distance and force at the finishing time of 10 seconds.

As you observed in Exploration 1, the external force applied by the hand is constant at all times. Does this imply that the acceleration is constant, getting less, or increasing during the motion sequence?

Note that the two masses are at rest at time zero. Use the final values of time and distance to calculate the acceleration in m/s2, without using the on-screen value of the force. In other words, use the kinematic equations to calculate the acceleration.

Reverse the direction with the toggle, and find the acceleration without using the on-screen value of the force. Take particular care with the signs in calculating this acceleration."

Newton's Second Law

Exploration 1

Push the direction toggle so the direction arrow points in the positive direction. Is this direction to your left or to the right? Also, before proceeding, reset the positions of the two masses to zero.

Start the simulation and observe the masses, as they accelerate to the right on a frictionless surface and eventually disappear off the screen.

Observe the on-screen values of time, distance and force and notice that the force remains constant throughout the motion.

Record the final values of distance and force at the finishing time of 10 seconds.

Exploration 2

As you observed in Exploration 1, the external force applied by the hand is constant at all times. Does this imply that the acceleration is constant, getting less, or increasing during the motion sequence?

Note that the two masses are at rest at time zero. Use the final values of time and distance to calculate the acceleration in m/s2, without using the on-screen value of the force. In other words, use the kinematic equations to calculate the acceleration.

Reverse the direction with the toggle, and find the acceleration without using the on-screen value of the force. Take particular care with the signs in calculating this acceleration."

Active Figure 4.13 Pushing Blocks With A Constant Force n the simuletion below, you cen observe the effects of a force applied to a two-block system Instructions: Use the directian taggle (dr'n) to set the direction othe external farce, and click start to apply the forc Newton's Second Law Push the direction tooale so the direction arrow points in the positive direction. Is this direction to your left or to the right? Aso, before proceeding, reset the positions of the two masses to zero. Start the simulation and observe the mascs they accclcrate to the right on a frictionicss surface and eventually disappear off the screen. Cbserve the on-screen values of tima, distance and forca and notice that the force remains constant throughout the motion Record the final velve5 of distence nd force at the finishing time of 10 seconds Exploration 2 As you observed in Exploration 1, the external force applied by the hand is constent at al times. Does this imply that the acceleration is constant, getting less, or increasi ng during the motion sequence? Nate that the t at rest at time zro.sthe fotime and distance to clculats the acceleration in m/2, without uzing the ou of the force. In other words, use the kinematic equations to caloulate the acccleration Ravarse the direction with the toggle, and find the accelaration without using the an-screen value of the forca. Take partioular care with the sig in calculating this acceleration. Display in a Now Windon

Explanation / Answer

m1 = 13.5 kg

m2 = 6 kg

a = 1.82 m/s^2

f) F = (m1 + m2)*a = (13.5 + 6)*1.82 = 35.49 N

g) P21 = P12 = m2*F/(m1 + m2) = 6*35.49/(13.5 + 6) = 10.92 N

h) P21 = P12 = m1*F/(m1 + m2) = 13.5*35.49/(13.5 + 6) = 24.57 N

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