use g = 10. mS2 Highlight the correct answer. Some questions have two words that
ID: 1784661 • Letter: U
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use g = 10. mS2 Highlight the correct answer. Some questions have two words that Conclusion Questions: need to be bolded and underlined. 1. At the highest point kinetic energy is minimun/macimun while the potential energy is minimmImaxim. 4 pts 2. At the lowest point kinetic energy is minimm/maximun while potential energy is minimum/ maximun. 4 pts 3. Mass affects/does not affect the conservation of energy. 2 pts 4. How much potential energy does the 60, kg skater have before she starts her ride, 12 m above the ground? 2 pts Answer Answer Answer] 5. How much kinetic energy does a 60.0 kg skater have traveling with a velocity of 4 m/s? 2 pts 6. How fast must a 20. 0 kg skater travel to have a kinetic energy of 360 Joules? 2 pts 7. How high must a 2.0 kg basketball be thrown so it has a potential energy of 160J? 2 pts 8. How fast must the 2.0 kg basketball te thrown upward to achieve the same potential energy of 160 3? 2 pts 9. A 75 kg skater starts his skate with an initial speed of 0.0 m/s, 8.0m above the ground. Just before he reaches the Answer Answer] ground what will be his velocity? 2 pts AnswerExplanation / Answer
1.At highest point K.E. is minimum while P.E. is maximum.
2.At lowest point P.E. is minimum while K.E. is maximum.
3.Mass does not affects the conservation of Energy.
4. P.E.=mgh=60.0 x 10 x 12 =7200 J
5. K.E.=0.5 x m x v2=0.5 x 60 x 4 x 4=480 J
6. K.E.=0.5 x m x v2=> v2= 2 x 360 / 20 =36 => v=6 m/s
7. P.E.=mgh => h=160/2x10 =8 m/s
8. K.E. = P.E. = >0.5 x m x v2=160 => v2= 160x2/2=> v=12.6491 m/s
9. K.E. = P.E. =>0.5 x m x v2=mgh=> v2= 2xgxh = 2x10x8.0 => v=12.6491 m/s
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