previous 8 of 13 roblem 29.27 Part A An electron moves in the magnetic field B-
ID: 1784676 • Letter: P
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previous 8 of 13 roblem 29.27 Part A An electron moves in the magnetic field B- 0.600 iT with a speed of 0 800 x107 m/s in the directions shown in the figure. For each, what is magnetic force F on the electron? aurel) Express vector F in the form of F. Fy. F, where the x, y, and z components are separated by commas. Submit My Answers Give Up Paree Express vector F in the form of F. F, F., where the x y, and z components are separated by commas. Figure 1 of Submit My Answers Giee U Provide Feedback CExplanation / Answer
a) The force on a charged particle moving in an external magnetic field will follow:
F = q(v x B)
The angle between the velocity vector and magnetic field vector is 90 degrees
F = qvB*sin = -1.6*10^-19*0.8*10^7*0.6*sin90 = -7.68*10^-13 N
The velocity and magnetic field vectors form a plane on the x-y plain. Using the right hand rule,
the force is pointing in the positive z-direction.
F = (-7.68*10^-13 k^) N
b) The velocity vector can be written like:
v = vx i^ + vy j^ + vz k^
vx = 0 m/s
vy = -v*cos45
vz = v*sin45
Now solve for the force vector F = q*v x B
F = qv(-cos45 j^ + sin45 k^) x (0.60 i^)
= -1.6*10^-19*0.8*10^7*[cos45*0.6 k^ + sin45*0.6 j^]
= (-5.43*10^-13 N) (j^ + k^)
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